5x -3 = 11 + 12x combine like figures add 3 to both sides to remove the 3 5x= 14+ 12x Now I get confused. If I remove the 12x I have to subtract 12x from 5x which gives me an answer of -7x=14 would the correct answer thus be x=
Solve the system:4x+2y-13=0 and 3x=5y+26 by elimination. 3 (4x+2y-13=0) 12x+6y-26=0 4 (3x=5y+26) 12x=20y+104 I need to subtract since the signs are the same: 12x+6y-26=0 Since they don't match up, I'm having trouble subtracting
Could you help me with the following problem, I don't understand how to do it. Am I suppose to use the linear factorization theorem? Find an nth degree polynomial function with real coefficients satisfying the given conditions. 1.
how do i do x2+12x+32 x2+12x = 14x+32 subtract 14x from each side 14x=32 divide by 2 7x=16 x=16/7, which is 2 and 2/7 ok maybe you typed that question wrong? is it x^2 + 12x + 32 ? if it is then the solution is: (x+8)(x+4) because
1) The sides of the triangle shown increase in such a way that (dz/dt=1) and (dx/dt=(3dy/dx)) At the instant when x = 12 and y = 5, what is the value of dx/dt? 2) Let f(x) = x^3 − 4. Which of these is the equation for the normal