# algebra 2

1. 0
2. 1
1. X^4/12 + 6X^3/7 + 3X^2/8 + 5 7X^4/12
+ 5X^2/8 - 5.

LCD = 168.

(14X^4 + 144X^3 + 63X^2 - 98X^4 + 105X^2) / 168,
Combine like-terms:
(-84X^4 + 144X^3 + 168X^2) / 168,

Factor out 12X^2:
12X^2(-7X^2 + 12X + 14) / 168,
Divide numerator and denominator by 12 and get:
X^2(-7X^2 + 12X + 14) / 14.

posted by Henry

## Similar Questions

1. ### algebra2

1/3 - 5/6 = 1/X SOLVE 1/3 - 5/6 = 1/X Let's remove the denominators by multiplying by 12X 12X*(1/3) - 12X*(5/6) = 12X*(1/X) Clear the fractions. 4X - 10X = 12 -6X=12 multipy by -1 6X=-12 Divide both sides by 6 6X/6 = -12/6 X = -2
2. ### calc

What is dy/dx of y=12/12X-y^3 ???? Any idea anyone??? y=12/12X-y^3 I assume you mean... y=12/(12X-y^3) 12Xy-y^4=12 12x dy/dx + 12y -4y^3 dy/dx=0 dy/dx (12x -4y^3)=-12y solve for dy/dx
3. ### algebra

5x -3 = 11 + 12x combine like figures add 3 to both sides to remove the 3 5x= 14+ 12x Now I get confused. If I remove the 12x I have to subtract 12x from 5x which gives me an answer of -7x=14 would the correct answer thus be x=

Evaluate a/b+c^d for a=6,b=3,c=4 and d=5 A.42*** B.18 C.82 D.360 What is the simplified form of the expression ? -(12x-8y) A.12x+8y B.12x-8y***** C.-12x+8y D.-12x-8y
5. ### math

Solve the system:4x+2y-13=0 and 3x=5y+26 by elimination. 3 (4x+2y-13=0) 12x+6y-26=0 4 (3x=5y+26) 12x=20y+104 I need to subtract since the signs are the same: 12x+6y-26=0 Since they don't match up, I'm having trouble subtracting