find the slope of the tangent to the curve:
y^2=x^3/xy
I will assume you meant
y^2 = x^3/(xy)
then ...
y^2 = x^2/y
y^3 = x^2
3y^2 dy/dx = 2x
dy/dx = 2x/(3y^2)
y^2=x^3/xy
y^2 = x^3/(xy)
then ...
y^2 = x^2/y
y^3 = x^2
3y^2 dy/dx = 2x
dy/dx = 2x/(3y^2)