Suppose a basketball player, Player A made 80% of her free throws last season and that she continues to shoot free throws at the same rate. Assume that free throw attempts are independent. Let the random variable X be the number of free throws that player A makes in her next 10 attempts.
a. what is the distribution
b. probability player A makes all 10
c.probabiliity makes at least 8
d.makes between 5 and 9
You can find the probabilities by using a binomial probability table or do these problems by hand using the following:
P(x) = (nCx)(p^x)[q^(n-x)]
n = 10
p = .80
q = 1 - p
I'll give you some hints:
b. Find P(10).
c. Find P(8), P(9), and P(10), then add together for total probability.
d. I'll let you determine this one.
posted by MathGuru
.869posted by Anonymous