write the formulas of the complex ion formed between

a) the ligand, Cl-, and the platinum(II) ion with a coordination number of four.

b) the ligand, NH3, and the nickel(II( ion with a coordination number of six.

c)the ligand, ethylenediamine, and the chromium (III) ion with a coordination of number six.

d) the ligand, dihydrogen ethylenediaminetetraacetate, abbreviated H2Y^2- and the zinc(II) ion with a coordination number of four.

a) In order to determine the formula of the complex ion formed between Cl- ligand and platinum(II) ion with a coordination number of four, we need to note that the overall charge of the complex ion should be zero.

Since the chloride ion (Cl-) has a charge of -1, and there are four chloride ions surrounding the central platinum ion, the total charge of the chloride ligands is -4.

The platinum(II) ion should have a charge of +2 to balance the overall charge of the complex ion at zero.

To form a neutral complex ion, we can have two chloride ions coordinated as monodentate ligands, meaning each chloride ion donates one electron pair towards the platinum(II) ion.

Therefore, the formula of the complex ion would be [PtCl2]2-.

b) For the complex ion formed between the ligand NH3 and the nickel(II) ion with a coordination number of six, we need to consider that the overall charge of the complex ion should be zero.

The ammonia ligand (NH3) is neutral i.e., it has no charge. Nickle(II) ion has a charge of +2.

Since the charge on the nickel(II) ion is +2, to balance the overall charge at zero, we need six NH3 ligands to form a neutral complex ion.

Each NH3 ligand donates one electron pair towards the nickel(II) ion, resulting in a coordination number of six.

Therefore, the formula of the complex ion would be [Ni(NH3)6]2+.

c) To determine the formula of the complex ion formed between the ligand ethylenediamine and the chromium(III) ion with a coordination number of six, we need to account for the overall charge of zero.

Ethylenediamine (en) is a bidentate ligand, meaning it can donate two electron pairs towards the central chromium(III) ion.

Since the chromium(III) ion has a charge of +3, to balance the overall charge at zero, we need three ethylenediamine ligands.

Each ethylenediamine ligand donates two electron pairs towards the chromium(III) ion, resulting in a coordination number of six.

Therefore, the formula of the complex ion would be [Cr(en)3]3+.

d) The ligand dihydrogen ethylenediaminetetraacetate (H2Y^2-) is a tetradentate ligand, meaning it can donate four electron pairs towards the central zinc(II) ion.

The dihydrogen ethylenediaminetetraacetate ligand contains two negatively charged acetate groups (CH3COO-) and two neutral amine groups (NH2).

Since the zinc(II) ion has a charge of +2, to balance the overall charge at zero, we need two dihydrogen ethylenediaminetetraacetate ligands.

Each ligand donates four electron pairs towards the zinc(II) ion, resulting in a coordination number of four.

Therefore, the formula of the complex ion would be [Zn(H2Y^2-)2]2+.