what are the theoretical mole ratios of copper(II) hydroxide and sodium sulfate?
To determine the theoretical mole ratios of copper(II) hydroxide (Cu(OH)2) and sodium sulfate (Na2SO4), we need to look at the balanced chemical equation for the reaction between the two compounds. The balanced chemical equation is:
Cu(OH)2 + Na2SO4 -> CuSO4 + 2NaOH
Based on this equation, we can deduce the following mole ratios:
1 mole of Cu(OH)2 reacts with 1 mole of Na2SO4.
So, the mole ratio of Cu(OH)2 to Na2SO4 is 1:1.
Similarly, 1 mole of Cu(OH)2 reacts to form 1 mole of CuSO4.
Therefore, the mole ratio of Cu(OH)2 to CuSO4 is 1:1.
Considering the reaction, we also find that 1 mole of Cu(OH)2 reacts to produce 2 moles of NaOH.
So, the mole ratio of Cu(OH)2 to NaOH is 1:2.
These are the theoretical mole ratios of copper(II) hydroxide and sodium sulfate based on the balanced chemical equation.