# Math

What is the real value of x in the equation log(subscript 2)24-log(subscript 2)3=log(subscript 5)x?

I really cannot remember at all how logs work. I know the answer is 125 but have no idea how to get there. Thanks in advance.

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1. Two things to remember

1. loga x = y is the same as ay = x

2. Log A - Log B = Log (A/B) as long as the bases are the same

so log(subscript 2)24-log(subscript 2)3=log(subscript 5)x

log2(24/3) = log5 x
log28 = log5 x
3 = log5 x
5^3 = x
125 = x

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