An astronaut on a strange planet finds that she can jump a maximum horizontal distance of 17.0 m if her initial speed is 3.80 m/s. What is the free-fall acceleration on the planet?
The horizontal distance traveled is given by d = V^2(sin(2µ))/g where V = the initial velocity, g = the acceleration due to gravity and µ = the initial angle of the velocity to the horizontal.
Since the maximum d will occur when µ = 45º. Therefore, d = 17 = 3.8^2(1)g. Solve for g.posted by tchrwill