In a distant planet, a freely falling object gains speed at a steady rate of 25 m/s during each 1.2 seconds of fall. The gravity acceleration there is:
122 m/s2
0.05 m/s2
30 m/s2
22 m/s2
5 m/s2
20.8 m/s2
a = 25m/s / 1.2s = 20.8m/s^2.
To solve this problem, we can use the formula for acceleration:
acceleration = change in velocity / time.
Given that the object gains speed at a steady rate of 25 m/s during each 1.2 seconds, we can calculate the acceleration as follows:
acceleration = 25 m/s / 1.2 s = 20.8 m/s².
Therefore, the gravity acceleration on the distant planet is 20.8 m/s².