i solved by factoring like this:
3x^2+5x-12=0
(3x+4)(x-3)
-4 +3
x=-4 x=3
now i need to solve by the form x^2=k
How do I do that?
3x^2 + 5x - 12 = 0
This cannot be factored
This can be solved by completing the square or using the quadratic formula.
(3x + 4)(x - 3) = 3x^2 - 5x - 12
Does not equal 3x^2 + 5x - 12
just switch your signs
3x^2+5x-12=0
(3x-4)(x+3) = 0
so 3x-4 = 0 or x+3 = 0
x = 4/3 or x = -3
your version would give a middle term of -5x
To solve the equation using the form x^2 = k, you would need to isolate the x^2 term on one side of the equation. However, in the given equation 3x^2 + 5x - 12 = 0, the x^2 term is already isolated on the left side.
So, let's use the factored form of the equation: (3x + 4)(x - 3) = 0.
To solve for x using the form x^2 = k, you would set each factor equal to zero and solve for x:
Setting 3x + 4 = 0:
3x = -4
x = -4/3
Setting x - 3 = 0:
x = 3
Therefore, the solutions to the equation 3x^2 + 5x - 12 = 0, when expressed in the form x^2 = k, are:
x = -4/3 and x = 3.