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A point charge of 1.8 uC is at the center of a Gaussian cube 55 cm on edge. What is the net electric flux through the surface?

I have no idea where to start with this problem.

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Scott

  1. According to Gauss' Law, you will get the same answer no matter where the charge q is placed inside the box, and no matter how large the box is. It does not even have to be a cube, as long as it encloses the charge.

    Total flux = q/(epsilon-zero)
    = 1.8*10^-6/8.82*10^-12
    = 2.04*10^5 (N*m^2/C)

    That is a lot easier than doing the actual integhtration of E(normal) over the six sides of the cube, but the answer will be the same.

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    drwls

  2. Can u pls explain with examples

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    Tejas

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