pre calculus

solve the equation. give an exact solution, and also an approximate solution to four decimal places.


2^(9x-7)=7

My first step was to change it to
log(base 2) 7 = 9x-7
i got 1.0897
Did i do something wrong or did i miss one question?

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  1. just take log of both sides

    log (2^(9x-7)) = log 7
    (9x-7) log2 = log7
    9x - 7 = log7/log2
    etc.

    your answer is correct, see

    http://www.google.ca/search?hl=en&source=hp&q=%28%28log%287%29%2Flog%282%29%2B7%29%2F9&btnG=Google+Search&aq=f&aqi=&aql=&oq=

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    posted by Reiny
  2. [9x -7] log 2 = log 7
    Any log base can be used, as long as it is the same for both sides.
    9x - 7 = 2.807
    9x = 9.807
    x = 1.0897

    Your answer is correct!

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    posted by drwls

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