The Everton college store paid $1668 for an order of 44 calculators. The store paid $8 for each scientific calculator. The others, all graphing calculators, cost the store $55 each. How many of each type of calculator was ordered?
Sorry! Actually, it was $8 the store paid, intead of $18. All else is correct. Thank you.
same way anyway
1668 = 8 x + 55 (44-x)
DON'T CARE GIVE ME ANSWER
No problem! Let's solve the problem with the updated information.
Let's assume the number of scientific calculators is represented by 'x', and the number of graphing calculators is represented by 'y'.
Given that the total cost of the order was $1668, we can form an equation:
8x + 55y = 1668
Since we also know that there were 44 calculators in total, we can write another equation:
x + y = 44
Now we have a system of equations. We can solve this system to find the values of 'x' and 'y'.
One way to solve the system is by substitution. Rearrange the second equation to solve for 'x':
x = 44 - y
Substitute this value of 'x' into the first equation:
8(44 - y) + 55y = 1668
Expand and simplify:
352 - 8y + 55y = 1668
Combine like terms:
47y = 1316
Divide both sides by 47:
y = 28
Substitute this value of 'y' back into the second equation to find 'x':
x + 28 = 44
x = 44 - 28
x = 16
Therefore, 16 scientific calculators and 28 graphing calculators were ordered.