In a gift wrapping department, a customer can choose from x different papers, y different ribbons, and z different greeting cards. There are 160 different paper, ribbon, and greeting card combinations. List three of the possible combinations.
Please see answer I pasted below. This question was answered by Damon yesterday.
math - Damon, Wednesday, February 2, 2011 at 7:40pm
1 1 1
1 1 2
1 1 3 assuming at least 3 greeting card choices
In a gift wrapping department, a customer can choose from X different papers, Y different ribbons, and Z different greeting cards. There are 160 different paper, ribbon, and greeting card combinations possible. List three of the possible combinations.
To find three possible combinations of papers, ribbons, and greeting cards, we need to know the values of x, y, and z. Unfortunately, the values of x, y, and z are not provided in the question.
However, we are given that there are 160 different combinations in total. This information can help us find the values of x, y, and z using algebra.
Let's assume x, y, and z are positive integers.
We can set up the equation:
x * y * z = 160
We need to find three different combinations, so let's set up a table to make it easier to visualize:
Combination 1: Paper 1, Ribbon 1, Greeting card 1
Combination 2: Paper 1, Ribbon 1, Greeting card 2
Combination 3: Paper 1, Ribbon 1, Greeting card 3
Now, let's find the values of x, y, and z that satisfy the equation:
1 * 1 * z = 160
z = 160
By solving the equation, we find that z needs to be equal to 160.
Therefore, three possible combinations can be:
Combination 1: Paper 1, Ribbon 1, Greeting card 1
Combination 2: Paper 1, Ribbon 1, Greeting card 2
Combination 3: Paper 1, Ribbon 1, Greeting card 3