Suppose two gases in a container have a total pressure of 1.20 atm. What is the pressure of gas B if the partial pressure of gas A is 0.75 atm?
Suppose two gases in a container have a total pressure of 1.20atm what is the pressure of gas B if the partial pressure of gas A is 0.75atm? Read more:
google told me its 0.45
To find the pressure of gas B, we need to subtract the partial pressure of gas A from the total pressure of both gases.
The partial pressure of gas B can be calculated by subtracting the partial pressure of gas A from the total pressure:
Partial pressure of gas B = Total pressure - Partial pressure of gas A
Partial pressure of gas B = 1.20 atm - 0.75 atm
Partial pressure of gas B = 0.45 atm
Therefore, the pressure of gas B is 0.45 atm.
To find the pressure of gas B, we first need to understand the concept of partial pressure.
Partial pressure is the pressure exerted by an individual gas in a mixture of gases. It can be calculated by multiplying the total pressure of the gas mixture by the mole fraction of the gas in the mixture.
In this case, the partial pressure of gas A is given as 0.75 atm, and the total pressure of the gases in the container is 1.20 atm.
To find the pressure of gas B, we can subtract the partial pressure of gas A from the total pressure:
Pressure of gas B = Total pressure - Partial pressure of gas A
Pressure of gas B = 1.20 atm - 0.75 atm
Pressure of gas B = 0.45 atm
Therefore, the pressure of gas B is 0.45 atm.