A stationary 1.67 kg object is struck by a stick. The object experiences a horizontal force given b F = at-bt^2, where t is the time in milliseconds from the instant the stick first contacts the object. If a = 1500 N/ms and b = 20N/ms^3, what is the speed of the object just after it comes away from the stick (t=2.74ms)?

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  1. Based upon the dimensions of b and the value of t when the object comes away, I believe you have copied the problem incorrectly. It should be

    F = at-bt^3

    in which case F = 0 at t = 2.74 ms

    Integrate F dt from t=0 to t=2.74 ms

    Express the answer in Newton*seconds
    (not Newton*milliseconds)

    That will equal the momentum of the released ball.

    Use that and the mass to get the velocity.

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