A 55.0-kg skydiver free falls for a period of time before opening his parachute. What is his kinetic energy when he reaches a velocity of 16.0 meters/second?
7040 J
Kinetic Energy = (1/2) M V^2
You should be familiar with that equation/definition.
Do the calculation.
To find the kinetic energy of the skydiver, you can use the formula:
Kinetic Energy (KE) = 1/2 * mass * velocity^2
Given:
Mass (m) = 55.0 kg
Velocity (v) = 16.0 m/s
Now you can substitute these values into the formula to find the kinetic energy:
KE = 1/2 * 55.0 kg * (16.0 m/s)^2
First, let's square the velocity term:
KE = 1/2 * 55.0 kg * (256.0 m^2/s^2)
Next, multiply the mass and velocity terms:
KE = 1/2 * 55.0 kg * 256.0 m^2/s^2
Finally, calculate the result:
KE = 7040 J
Therefore, when the skydiver reaches a velocity of 16.0 meters/second, his kinetic energy is 7040 Joules.