# of rabbits/ Liter:
1 2 3 4 5 6 7 8 9 10 11 12
Liters:
1 3 5 9 10 8 4 4 3 5 3 1
Is the 1-rabbit liter and outlier???
Correction on the spelling on the question:
Is the 1-rabbit an outlier??
W-WAIT!
Spelling correction:
Is the 1-rabbit liter an outlier????
To determine if the 1-rabbit liter is an outlier, we need to calculate the median and interquartile range (IQR) of the data.
First, let's arrange the liters in ascending order:
1, 1, 3, 3, 3, 4, 4, 5, 5, 8, 9, 10
Next, let's find the median, which is the middle value of the data set. In this case, we have 12 data points, so the median would be the average of the 6th and 7th values, which are 4 and 4. Therefore, the median is 4.
To calculate the IQR, we need to find the first quartile (Q1) and the third quartile (Q3). Q1 is the median of the lower half of the data, and Q3 is the median of the upper half.
In this case, the lower half consists of the first 6 data points: 1, 1, 3, 3, 3, 4. The median of this lower half is the average of the 3rd and 4th values, which are 3 and 3. Therefore, Q1 is 3.
The upper half consists of the last 6 data points: 4, 4, 5, 5, 8, 9. The median of this upper half is the average of the 3rd and 4th values, which are 5 and 5. Therefore, Q3 is 5.
To calculate the IQR, we subtract Q1 from Q3:
IQR = Q3 - Q1 = 5 - 3 = 2
Now, to determine if the 1-rabbit liter is an outlier, we can use the following rule:
- Any value below Q1 - (1.5 * IQR) or above Q3 + (1.5 * IQR) is considered an outlier.
In this case, Q1 is 3 and the IQR is 2. Therefore, the lower threshold would be Q1 - (1.5 * IQR) = 3 - (1.5 * 2) = 0, and the upper threshold would be Q3 + (1.5 * IQR) = 5 + (1.5 * 2) = 8.
The 1-rabbit liter is below the lower threshold of 0, so it is considered an outlier.