I have worked this and checked it and it does not come out true any one help me?
3x-5(3x-7)=2(x+9)+45
3x-15x-35=2x+18+45
-12x-35=2x+63
+35 +35
-12x=2x+98
-2x -2x
-10x=98
x=-98/10
x=-9 8/10
checking it i get 152 3/5 and 43 2/5
Help where did I go wrong?
I KNOW I KNOW! When you distribute -5 to -7 in the beginning its 35 not negative 35.
I figured it out I miss added two negatives.
You mean miss multiplied.
Thanks.
To understand where you went wrong, let's go through the steps of solving the equation again:
Starting with the given equation:
3x - 5(3x - 7) = 2(x + 9) + 45
First, we need to distribute the -5 and the 2:
3x - 15x + 35 = 2x + 18 + 45
Combining like terms on both sides:
-12x + 35 = 2x + 63
Now, let's identify the error in your calculation:
You added 35 to both sides correctly, but you made a mistake when combining the like terms on the right-hand side.
Instead of writing "-12x = 2x + 98", the correct step should be:
-12x + 35 = 2x + 63
-12x = 2x + 28
Next, to solve for x, we need to isolate the variable terms on one side:
-12x - 2x = 28
Simplifying further:
-14x = 28
Finally, to find the value of x, divide both sides of the equation by -14:
x = -28 / -14
x = 2
So, the correct solution to the equation is x = 2.
Now, let's check the solution:
Substituting x = 2 back into the original equation:
3(2) - 5(3(2) - 7) = 2(2 + 9) + 45
6 - 5(6 - 7) = 2(11) + 45
6 - 5(-1) = 22 + 45
6 + 5 = 67
The left-hand side does not equal the right-hand side. Therefore, there is no solution to the original equation.