3x+5y=0 2x-5y=-9

idk how 2 solve it then graph it my teacher eont help me plzz help

I assume you need to solve these equations simultaneously ?

3x + 5y = 0
2x - 5y = -9

Solving by elimination method. The object is to eliminate one of the variables, either x or y.

Since you have +5y in the first equation and -5y in the second equation, you ADD the two equations.
This is because +5y + -5y = 0.

3x + 5y = 0
2x - 5y = -9
5x + 0 = -9
5x = -9
Divide both sides by 5
x = -9/5

To find y, substitute x = -9/5 in either equation and solve for y.
3x + 5y = 0
x = -9/5
3(-9/5) + 5y = 0
-27/5 + 5y = 0
Add 27/5 to both sides
-27/5 + 27/5 + 5y = 27/5
5y = 27/5
Divide both sides by 5
y = 27/5 /5
Multiplying the numerator by the reciprocal of the denominator is the same as dividing.

y = 27/5 * 1/5
y = 27/25

I'll leave the check to you.
x = -9/5, y = 27/5

o ok ty

You're welcome.

I'd be happy to help you solve the system of equations and graph it. To get started, we can use one of several methods to solve the system of equations. One common method is substitution. Here's a step-by-step explanation of how to solve it using substitution:

1. Solve one of the equations for one variable in terms of the other variable. Let's solve the first equation for x:
3x + 5y = 0
Subtract 5y from both sides:
3x = -5y
Divide both sides by 3:
x = -5/3y

2. Substitute the expression for x in terms of y into the second equation:
2x - 5y = -9
Substitute the value of x:
2(-5/3y) - 5y = -9
Simplify the equation:
(-10/3)y - 5y = -9
Multiply through by 3 to eliminate the fraction:
-10y - 15y = -27
Simplify further:
-25y = -27

3. Solve for y:
Divide both sides by -25:
y = -27/-25
Simplify the fraction:
y = 27/25

4. Substitute the value of y into the expression we obtained for x:
x = -5/3y
x = -5/3(27/25)
Simplify the expression:
x = -9/5

Now we have the solution to the system of equations: x = -9/5 and y = 27/25.

To graph the solution, you can create a coordinate plane by drawing two perpendicular axes (x-axis and y-axis). Plot the point (-9/5, 27/25) as a single point on the graph. This represents the intersection of the two lines given by the equations.

Hope this helps! Let me know if you have any more questions.