Calc
lim as x > infinity of (x^216)/(x4) is 8
By graphing, find an interval for near zero such that the difference between your conjectured limit and the value of the function is less than 0.01. In other words, find a window of height 0.02 such that the graph exits the sides of the window and not the top or bottom. What is the window?
____≤ x ≤_________
____ ≤ y ≤ ________
I'm confused on how to find these intervals with the given 0.01 and 0.02. Thanks!

the limit of (x^216)/(x4) as x > infinity is infinity, not 8
lim (x^216)/(x4) as x > 4 is 8
= lim (x+4)(x4)/(x4) as x>4
= lim x+4 as x >4
= 4 + 4 = 8posted by Reiny

Sorry! That was a typo. It was as the limit approaches 4. I'm still confused on how to find the y intervals.
posted by Josie
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