72.0 ml of a 1.50 M solution is diluted to a volume of 288 mL. A 144 mL portion of that solution is diluted using 185 mL of water. What is the final concentration?

I answered this question late last night. Look at one of your earlier postings. If you can't find it perhaps I can find a link for you.

To find the final concentration, we need to calculate the amount of solute before and after dilution.

First, let's calculate the amount of solute before dilution:
Amount of solute before dilution = initial volume × initial concentration
Amount of solute before dilution = 72.0 ml × 1.50 M
Amount of solute before dilution = 108.0 mmol

Next, let's calculate the amount of solute after dilution:
Amount of solute after dilution = final volume × final concentration

Since the 144 mL portion is diluted with 185 mL of water, the final volume will be the sum of the two:
Final volume = 144 mL + 185 mL
Final volume = 329 mL

Now we can find the final concentration:
Final concentration = Amount of solute after dilution / Final volume
Final concentration = 108.0 mmol / 329 mL

To convert mL to L, divide by 1000:
Final concentration = 108.0 mmol / 0.329 L

Calculating this:
Final concentration ≈ 328.54 mmol/L

Therefore, the final concentration is approximately 328.54 mmol/L.