physics

A charge Q = -520 C experiences a downward force of 0.04 N. What is the electric field in N/C at the point where the charge is located? Take upward to be positive.

I know that E=Kq/r^2
therefore
E= (9.0*10^9Nm)(-520*10^-6c)/r^2
I'm not sure how to get the distance and what I'm suppose to do with the force.

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asked by help
  1. Never mind I figured it out:)

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    posted by help
  2. E= 2.5 X 10^5 N/C

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    posted by David

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