Respond to this Question
Similar Questions

PLEASE HELP!!!!
if log6=m and log 5=n, write 7.2 as an expression in m and n Answer is 2mn Please help me!!
asked by Sabrina on January 20, 2011 
Math
The problem I have to solve is log with base 2 ^6 multiply by log base 6 ^ 8. I use the change of base formula and got log6/log2 * log8/log6 Which become log6/log2 * log2()^3/ log 6 I'm stuck here thanks.
asked by Shadow on June 18, 2013 
pre calculous
use the properties of logarithms to write the expression as a sum or difference of logarithms or multiples of logarithms. show your work ln x^2/y^3 Assuming x,y AND z are positive use properties of logariths to write the
asked by kevin on June 12, 2011 
college algebra
Write expression as one logarithm and simplify if appropriate. log 3√x + log x^4  log x^3 4 log (x+3)  5 log (x^2+4) + 1/3 log y I have these who problems but I don't know where to start. HELP Please.
asked by Deb on April 17, 2013 
Precalculus
1. Write the given expression as a single logarithm. log(70x)+log(10y)2 2. Simplify the expression. (Do not use mixed numbers in your answer.) (5x^7/8)(2y^4/6)(x^9/8)(4y^2/6) 3. Write the given expression as a single logarithm.
asked by Anonymous on November 6, 2010 
Math (precelc 12)
Write the expression as a single logarithm: 3log(a)log(b)(1/2)log(c) I want to check my answer. I got log(a^3/bc^(1/2))
asked by Jana on May 30, 2016 
Algebra
1)If y varies inversely as x and y = 3, when x = 6. Find y when x = 36. A)72 B)2 C)1/2 D)18 I chose C y1/x2 = y2/x1 3/36 = y2/6 18/36 = 1/2 2)Write the equation 4^3 = 1/64 in logarithmic form. A)log64 = 4^3 B)log^3 64 = 4
asked by Jon on February 22, 2008 
Calculator Help
Is there a difference between TI89 Titanium calculator and TI83 calculator? Because I'm taking a final exam and my teacher will only allow us to use a TI83 calculator and I've never used it... like for putting in the
asked by Amy~ on June 2, 2010 
Precalc
Using logarithms to rewrite the expression: 1.) log4.(4)^3x= 2.) 6 log6 36= 3.) 3 log 2 1/2= 4.) 1/4 log4 16
asked by Anonymous on February 25, 2016 
Calculus
Integrate x dx/(1x). I have proceeded thus Int xdx/(1x)=int (x1+1)/(x1) =Int[1+ 1/(x1)]dx =Int dxInt dx/(x1) =xlog(x1). On differentiating, we get original expression d/dx[xlog(x1)]=11/(x1)=x/(x1)=x/(1x).
asked by MS on January 8, 2014