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2 isosceles triangles have the same height. The slopes of the sides of triangle A are double the
slopes of the corresponding sides of triangle B. How do the lengths of their bases compare?

A. The base of A is quadruple that of B. The base of A is double that of B.
C. The base of A is half that of B.
D. The base of A is one quarter that of B.

I thought it would be B, but its A, how?

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  1. let the height of both triangles be h
    let the base of triangle A be 2x
    let the base of triangle B be 2y

    slope of side of A = h/x
    slope of side of B = h/x

    but h/x = 2 (h/y
    1/x = 2/y
    y = 2x
    or

    x = (1/2)y ----> base of A is half that of B

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  2. I still dont' get how it the base is half the size?

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