Compare the gravitational force on a 35 kg
mass at the surface of the Earth (with radius 6.4 × 10
6
m and mass 6 × 10
24
kg) with
that on the surface of the Moon
�
with mass
1
81.3
ME and radius 0.27RE
�
.
What is the force on the moon?
To compare the gravitational force on the 35 kg mass at the surface of the Earth with the force on the surface of the Moon, we need to use the formula for gravitational force:
F = (G * m1 * m2) / r^2
Where:
F = Gravitational force
G = Universal gravitational constant (approximately 6.674 x 10^-11 N(m/kg)^2)
m1 = Mass 1
m2 = Mass 2
r = Distance between the centers of the two objects
Let's calculate the gravitational forces on the 35 kg mass at the surface of the Earth and the Moon separately.
Gravitational force on the surface of the Earth:
Mass of Earth (m1) = 6 x 10^24 kg
Mass of the object (m2) = 35 kg
Radius of Earth (r) = 6.4 x 10^6 m
Plugging these values into the formula, we get:
F1 = (6.674 x 10^-11 N(m/kg)^2 * (6 x 10^24 kg) * (35 kg)) / (6.4 x 10^6 m)^2
Calculating this equation will give us the gravitational force on the 35 kg mass at the surface of the Earth.
Gravitational force on the surface of the Moon:
Mass of Moon (m1) = 81.3 Earth masses = 81.3 * 6 x 10^24 kg
Mass of the object (m2) = 35 kg
Radius of Moon (r) = 0.27 * Radius of Earth (RE)
Plugging these values into the formula, we get:
F2 = (6.674 x 10^-11 N(m/kg)^2 * (81.3 * 6 x 10^24 kg) * (35 kg)) / ((0.27 * 6.4 x 10^6 m))^2
Calculating this equation will give us the gravitational force on the 35 kg mass at the surface of the Moon.
Once you have calculated both F1 and F2, you can compare them to determine the difference in gravitational force between the Earth and the Moon.