# mat h

ms. buxx invested a total of \$2000 in two savings accounts. The first account pays 3% interest per year and the second account pays 5% interest per yera. If the interest from both accounts totals \$84 per yera, how much is invested in each account?

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1. x = amt at 3%
y = amt at 5%

x + y = 2000
.03x + .05y = 84

solve simultaneously for x, y

give it a try, post if you need for help
x = 800, y = 1200 if you are right

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2. the answer is the first account has 800 and the second account has 1200

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3. I need the steps to this equation

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4. x+y=2000
.03x+.05y=84

x+y=2000
-x -x
y=-x+2000 y=-(800)+2000

.03x+.05(-x+2000)=84 y=1200
.03x+ -.05x +100=84
-.02x+100=84
-100 -100
-.02x=-16
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-.02x
x= 800

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