find the values of each of the following polynomials for the given values of the variable.
for x=-3 and for x=-2
-x^2-5x-6
how do i do the above i am not sure but have an idea can someone help?
All you have to do is plug x into the polynomial. For x=-3, you would have -(-3)^2-5(-3)-6. Simply that to get your solution (which should be just a number). Then, plug in -2 for the second part, simplify, and you're done.
how is this?
-(-3^2)-5(-3)-6=
-9+15-6=18 (18 is the answer?)
i have checked it about 5 times and posted my work, but the teacher stated that the answer is 0 i do not know how she got the answer it is driving me crazy. thank you for confirming my answer.
<< -9+15-6=18 >> ??
how did you get 18 for that?
-9+15-6
15-9-6
= 15-15
= 0
To find the values of the given polynomial when x is equal to -3 and -2, you simply substitute these values into the polynomial expression.
First, let's plug in x = -3:
-x^2 - 5x - 6
= -(-3)^2 - 5(-3) - 6
= -(9) + 15 - 6
= -9 + 15 - 6
= 6
So, when x = -3, the value of the polynomial is 6.
Now, let's plug in x = -2:
-x^2 - 5x - 6
= -(-2)^2 - 5(-2) - 6
= -(4) + 10 - 6
= -4 + 10 - 6
= 0
So, when x = -2, the value of the polynomial is 0.
In summary, when x is equal to -3, the value of the polynomial is 6, and when x is equal to -2, the value of the polynomial is 0.