Chemistry

I posted before about designing a procedure to determine two unknowns (1 solid, 1 solution). The possible solutions were: NaCl, CaCl2, CuSO4, NaOH,Ba(OH)2, HCl, HNO3, or H2O. The reagents given are: NaOH, HCl, AgNO3, Zn metal, Na2SO4, and H2O.

The procedure I've designed so far is:
1) Look at colour, if blue, it is CuSO4
2) Test a bit of unknown with Zn. If there is a reaction it has hydrogen.
3) Add AgNO3, if there is no reaction, it is HCl or KNO3.
4) Add HCl and Na2SO4, if no reaction it is Ba(OH)2.
5) Add HCl and Zn, if no reaction it is NaOH.
6) Add AgNO3, if no reaction it is H2O.
7) Add Na2SO4, if no reaction, it is CaCl2.
8) It is NaCl

Can someone please check over this to see if this would work?

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  1. The procedure I've designed so far is:
    1) Look at colour, if blue, it is CuSO4. OK

    2) Test a bit of unknown with Zn. If there is a reaction it has hydrogen. I don't know what you have in mind but this won't tell you much unless it's HNO3 or HCl and litmus paper might do just as well. How will you know it is hydrogen?

    3) Add AgNO3, if there is no reaction, it is HCl or KNO3. AgNO3 reacts with HCl to produce AgCl, an insoluble white ppt.

    4) Add HCl and Na2SO4, if no reaction it is Ba(OH)2. Separately or both at the same time? Na2SO4 and Ba(OH)2 produce a white ppt of BaSO4 insoluble in HCl or most anything else

    5) Add HCl and Zn, if no reaction it is NaOH. I don't understand this one either.

    6) Add AgNO3, if no reaction it is H2O. Why couldn't it be HNO3 or KNO3?

    7) Add Na2SO4, if no reaction, it is CaCl2. It could be any of those EXCEPT Ba(OH)2.

    8) It is NaCl I don't understand this one unless it's all that's left

    Here is a list of the solubility rules.

    http://www.chem.vt.edu/RVGS/ACT/notes/solubility_rules.html

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  2. balance the following double displacement reaction equations. indicate the precipitate with an (s) Pb(NO3)2 +HCl----->PbCl2 + HNO3.
    CaCo3 + HCl---->H2CO3 + CaCl2.

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