physics

The flow rate of a liquid through a 2.0cm radius pipe is 0.0080 m^3/s. the average fluid in the pipe is?

i know that Av=volume flow rate
for this problem the flow rate is 0.008m^3/s. Do i divide by the radius^2 to get velocity or is there someother equation im supposed to be using

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  1. Volume flow rate Q (which is 0.0080 m^3/s in your case) is always equal to the product of fluid velocity and the cross sectional area of the flow. In this case that area is pi*r^2, where r is the pipe radius.
    Therefore V = Q/(pi r^2)

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  2. 6.4 m/s

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  3. 0.64

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