Chemistry

Determine how many milliliters of 0.448 M HClO4 will be required to neutralize 38.30 g Ca(OH)2 according to the reaction: 2HCl+Ca(ClO4)2+2H20

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  1. You need to start from a balanced equation

    HClO4 + Ca(OH)2 -> Ca(ClO4)2 + H20

    which you need to balance

    2HClO4 + Ca(OH)2 -> Ca(ClO4)2 + 2H20

    then work out how many moles 38.30 g Ca(OH)2 represents from

    number of moles = 38.30 g/molar mass

    from the equation 2 mole of HClO4 needed for each mole of Ca(OH)2

    hence calcutae the number of moles of HClO4 needed.

    ml of HClO4 needed is then

    number of moles x 1000/(0.448 mole L^-1)

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    posted by Dr Russ

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