determine the new molarity of calcium ions when 50.0 mL of a 1.50 M calcium chloride solution are combined with 750.0 mL of a 0.236 M calcium phosphate solution.

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asked by Wade
  1. moles CaCl2 = M x L = ??
    moles Ca^+2 = same

    moles Ca3(PO4)2 = M x L = ??
    moles Ca^+2 = 3x that.

    Assuming the volumes are additive,
    M = total moles/total volume.

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