11th grade pre ap physics

An athlete whirls a 7.00 kg hammer tied to the end of a 1.1 m chain in a horizontal circle. The hammer makes one revolution in 0.9 s. What is the tension in the chain?

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asked by asian
  1. The speed of the hammer must be
    V = 2 pi*1.1/0.9 = 7.68 m/s. The chain cannot not be quite horizontal, but tipped at an angle A (to support the weight) so that
    M V^2/R = T cos A and
    M g = T sin A
    tan A = g R/V^2 = 0.183
    which means that
    A = 10.3 degrees
    T = (M V^2/R)/cos10.3 = ______

    If you do not include the cos 10.5 factor, your answer will be about 2% off.

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    posted by drwls
  2. This is the wrong answer, do not copy it

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    posted by Corey
  3. 396 (approx)

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    posted by vinay
  4. 396 N (approx)

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    posted by vinay
  5. A single electron is placed in an electric field where the intensity 103.5 N/c. What force does the electron experience?

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    posted by ShMuel

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