Pre-Calculus

translate this polar equation into a rectangular form:

rsin(2theta)=sin(theta)

My answer:

r2sin(theta)cos(theta)=sin(theta)
2rcos(theta)=1
2x=1
x=1/2

This is the only answer I can get and someone told me it's wrong. Would someone please help me with this

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asked by Sara
  1. or maybe the answer is:

    y=2xy

    but that's kind of weird

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    posted by Sara
  2. I don't know if this is right, but this is how I would work it.

    rsin (2 theta) = sin (theta)

    r (2 sin(theta) 2cos(theta)) = sin (theta) divide both sides by 2 sin
    r 2 cos (theta) = 1/2 divide both sides by 2
    r cos (theta) = 1/4
    x = 1/4

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    posted by Trevor

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