A window washer is standing on a scaffold supported by a vertical rope at each end. The scaffold weighs 210 N and is 2.80 m long. What is the tension in each rope when the 710 N worker stands 1.80 m from one end?

smaller and larger.

Draw a sketch:

T1================210N======710N=======T2

Take moments about the left:
T2*2.8 - 210*1.4 - 710*1.8 = 0
Solve for T2

Take moments about the right:
-T1*2.8 + 210*1.4 + 71-*(2.8-1.8) = 0
Solve for T1

i keep coming up with the wrong answer for T1. i am getting 358.57 and its wrong.

Unless your question takes T2 as the first answer, which is supposed to be (710+210)-358.57 = 561.43.

If that's not the case, verify
1. instruction for rounding of answers (to the nearest newton, two decimals, etc.)
2. order of the answers (which should add up to 710+210.
3. Check that the numbers posted correspond to the questions on the computer.
4. Sometimes after a wrong answer, the qustion gets modified by the computer. Make sure that did not happen.

To find the tension in each rope, we can start by analyzing the forces acting on the scaffold.

There are three forces acting on the scaffold:
1. The weight of the scaffold (210 N) acting downward, which we'll call F_scaffold.
2. The weight of the worker (710 N) acting downward, which we'll call F_worker.
3. The tension in the ropes, acting at an angle from the vertical, which we'll call F_tension.

Since the scaffold is in equilibrium, the sum of the forces in the vertical direction must equal zero. Therefore, the tension in each rope will be equal to half the sum of the scaffold's weight and the worker's weight.

First, let's find the net vertical force acting on the scaffold:
F_net = F_scaffold + F_worker
F_net = 210 N + 710 N
F_net = 920 N

Now, let's find the tension in each rope:
Tension = F_net / 2
Tension = 920 N / 2
Tension = 460 N

Therefore, the tension in each rope is 460 N, both smaller and larger.

-210 (1.4)<--half of 2.80<-710 (1.8) + T2 (2.8)=

-294 - 1572 + 2.8 T2=0
-1866 = -2.8 T2
-1866 = T2
_____
2.8

6666= T2

now solve for T1

T1+ T2= weigh1g+ weight 2g
we move the T2 answer to right side
T1= 710 + 210 - 666
T1= 254 N