ALGEBRAIC FRACTIONS

find the illegal values of C in the multiplication statement c^2-3c-10/c^2+5c-14 . c^2-c-2/c^2-2c-15

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asked by K
  1. I will assume you mean
    (c^2-3c-10)/(c^2+5c-14) (c^2-c-2)/(c^2-2c-15)

    = (c-5)(c+2)/((c+7)(c-2)) (c-2)(c+1)/((c-5)(c+3))
    = (c+2)(c+1)/((c+7)(c+3)) c ≠ -7,-3, 2, 5

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    posted by Reiny

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