Math  Sum of a Series
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the sum of the first n terms of an arithmetic series is 51. the series has a constant difference of 1.5 and a first term of four. Find the number of terms in the sum I find using an EXCEL spreadsheet is very helpful for these
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Consider the infinite series of the form: (+/)3(+/)1(+/)(1/3)(+/)(1/9)(+/)(1/27)(+/)...(+/)(1/3^n)(+/)... (A) Find x and y from: x(
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Consider the infinite series of the form: (+/)3(+/)1(+/)(1/3)(+/)(1/9)(+/)(1/27)(+/)...(+/)(1/3^n)(+/)... (A) Find x and y from: x(
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Q.Determine the sum of each infinite geometric series. t_1= 8 r = 2^1/2  A.This is a divergent series because the absolute value of r is greater than 1.
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I need steps on how to complete this please i am so confused and lost. :( Consider the infinite geometric series x e n=1 4(1/3) n1. In this image, the lower limit of the summation notation is "n=1". a. Write the first four terms
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A geometric series has a positive common ratio of r. The series has a sum to infinity of 9 and the sum of the first two terms is 5. Find the first four terms of the series.
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Use the comparison or limit comparison test to decide if the following series converge. Series from n=1 to infinity of (4sin n) / ((n^2)+1) and the series from n=1 to infinity of (4sin n) / ((2^n) +1). For each series which
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A series of 288 consecutive odd integers has a nonzero sum that is a perfect fourth power. Find the smallest possible sum for this series.
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Another problem: determine whether the series is convergent if so find sum it is the sum from k=1 to infinity of ((1)^k)/(3^(k+1)) i found this series to be geometric where a=1/9 and r=1/3 my answer was converges to 1/6
asked by sarah on February 21, 2008 
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determine whether the series is convergent if so find sum it is the sum from k=1 to infinity of ((1)^k)/(3^(k+1)) i found this series to be geometric where a=1/9 and r=1/3 my answer was converges to 1/6
asked by sarah on February 21, 2008