# Physics

If you throw a cricket ball up into the air and the ball leaves your hand at 1.8m and travel with a speed of 9.7m s. What is the speed at the point it hits the floor. Accerlation due to gravity is 9.8 ms no air resistance

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1. No matter what angle you throw it at, the kinetic energy increases by
M g *1.8 m when it hits the ground. That means
(M/2)(V2^2 - V1^2) = M*g*1.8
Note that the mass M cancels.
V2^2 = 2*g*1.8m + V1^2
= 37.04 m^2/s^2 + V1^2
= 37.04 + 94.1

Solve for V1

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posted by drwls

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