A car starts from rest accelerates with a constant acceleration of 1.5 m/s squared. HOw far does the car move in 4 seconds?
x = (1/2) a t^2
(1/2) * 1.5 * 16 = ___ m
That is low acceleeration for a car:
0 to 60 mph in 17.8 seconds. That is why you will get a rather short distance travelled in 4 seconds.
12m
To find the distance covered by the car in 4 seconds, we need to use the equation of motion for uniformly accelerated motion:
s = ut + (1/2)at^2
Where:
s = distance covered
u = initial velocity (which is zero in this case, as the car starts from rest)
a = acceleration
t = time
Given:
u = 0 m/s (initial velocity)
a = 1.5 m/s^2 (acceleration)
t = 4 s (time)
To calculate the distance covered, substitute the values into the equation:
s = (0 m/s)(4 s) + (1/2)(1.5 m/s^2)(4 s)^2
Simplifying this equation gives us:
s = 0 + (1/2)(1.5 m/s^2)(16 s^2)
s = 0 + (1/2)(1.5 m/s^2)(16 s^2)
s = (1/2)(24 m)
s = 12 m
Therefore, the car moves a distance of 12 meters in 4 seconds.