physics

How much heat must be added to 0.55 kg of aluminum to change it from a solid at 180°C to a liquid at 660°C (its melting point)? The latent heat of fusion for aluminum is 4.0x10^5 J/kg.

I understand the Equation Q=mc times change it T
would that be .55 times 4.0 x 10^5 times (660-180) or im i mising something please help im still haveing some trouble with this problem

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asked by maria
  1. FIRST you must heat the Al from 180 to 660
    for that you need the heat capacity of Al, call it Cal, which is in your book.
    Q1 = .55 * Cal * (660-180)
    THEN you melt it
    Q2 = .55 * 4*10^5
    period, no temp in that eqn it happens at melting point

    Then add Q1+Q2

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    posted by Damon

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