please help dont know how to solve

The pole vault landing pad at an Olympic competition contains what is essentially a bag of air that compresses from its "resting" height of 1.1 m down to 0.1 m as the vaulter is slowed to a stop.
(a) What is the time interval during which a vaulter who has just cleared a height of 6.9 m slows to a stop?
s

(b) What is the time interval if instead the vaulter is brought to rest by a 19.2-cm layer of sawdust that compresses to 4.6 cm when he lands?
ms

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  1. Get speed when the vaulter hit the cushion
    (1/2) m v^2 = m g h
    v^2 = 2 g h = 2 * 9.8 * (6.9 - 1.1)
    v^2 = 134
    v = 10.7 m/s
    comes to a stop over one meter (1.1-.1)
    approximate by constant deacceleration
    0 =Vi + a t
    1 = Vi t + (1/2) a t^2

    a t = -10.7
    a = -10.7/t

    1 = 10.7 t + (1/2)(-10.7/t) t^2
    1 = 10.7 t - 5.35 t
    1 = 5.35 t
    t = 1/5.35 second

    do the second half the same way

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    posted by Damon
  2. i tried to solve for b but got it wrong. can you just tell me how i can get it started please.

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    posted by student
  3. i try to answer the problem i am stuck here is the problem 14 8/12 -10/11

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