# Physics

Consider the motion of a projectile. It isfired at t = 0. Its initial speed is 36 m/s and its initial projection angle is 55◦ from the horizontal.
The acceleration of gravity is 9.8 m/s2 . y
x
What is the maximum height, h, of its tra jectory?

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1. Maximum height is achieved when the velocity's vertical component is zero.

36*sin55 - gt = 0

Solve for the time t. Then use

y = 30*sin55* t - (g/2)t^2

to get the maximum altitude h.

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posted by drwls

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