geometry

find the area of a regular hexagon with the side length 4m. round to the nearest tenth

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asked by john
  1. The area of a regular hexagon of side 4m is the same as that of 6 equilateral triangles with side 4m.

    Area of an equilateral triangle
    A=s²*√(3)/4
    =4²*√(3)/4
    =4√(3)
    For the regular hexagon,
    6A=24√(3)

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    posted by MathMate

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