physics

A 10 kg block slides up a hill to a height of 5.8 m. If 414 J of thermal energy are generated, how fast was the block going at the bottom of the hill?

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asked by mas
  1. Initial kinetic energy = (1/2) M Vo^2
    = (thermal energy generated) + (potential energy increase)
    = 414 J + M g H = 982 J

    Solve for Vo

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    posted by drwls

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