algebra

To write the initial equation of a straight line 6x - 5y - 4z + 8 = 0.6x + 5y + 3z +4 = 0

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asked by Andruxa
  1. 6X - 5Y - 4Z -.6X -5Y - -3Z = 4 - 8,
    5.4X - 10Y - 7Z = -4,
    5.4X - 10Y - 7Z + 4 - 0

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    posted by Henry

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