Calculate the atomic mass of iridium. Iridium has two isotopes. Iridium-191 has a mass of 191.0 amu and a percent abundance of 37.58%. Iridium-191 has a mass of 193.0 amu and a percent abundance of 62.42%.
how do i do this
The atomic mass you see in the periodic table is a weighted AVERAGE of the isotopes according to their percent abundance.
(191.0*0.3758)+ (193.0*0.6242) = ??
so for this one would the answer be 192.2484 amu?
To calculate the atomic mass of iridium, we need to consider the mass and percent abundances of its two isotopes, iridium-191 and iridium-193.
Step 1: Convert the percent abundances to decimals.
- The percent abundance of iridium-191 is 37.58%, which is equal to 0.3758 in decimal form.
- The percent abundance of iridium-193 is 62.42%, which is equal to 0.6242 in decimal form.
Step 2: Multiply the mass of each isotope by its corresponding percent abundance.
- Multiply the mass of iridium-191 (191.0 amu) by its percent abundance (0.3758): 191.0 amu × 0.3758 = 71.85 amu.
- Multiply the mass of iridium-193 (193.0 amu) by its percent abundance (0.6242): 193.0 amu × 0.6242 = 120.48 amu.
Step 3: Add the results from Step 2 to calculate the atomic mass of iridium.
- Add the contributions of iridium-191 (71.85 amu) and iridium-193 (120.48 amu): 71.85 amu + 120.48 amu = 192.33 amu.
Therefore, the atomic mass of iridium is approximately 192.33 amu.
To calculate the atomic mass of iridium, you need to take into account the mass of each isotope and its respective percent abundance. Here's how you can calculate it:
1. Convert the percent abundances to decimal form. In this case, the percent abundances are already given in decimal form: 37.58% and 62.42%.
2. Multiply each isotope's mass by its percent abundance. For iridium-191, the mass is 191.0 amu and the percent abundance is 0.3758. Multiply these values together: 191.0 amu * 0.3758 = 71.9428 amu.
3. Repeat the multiplication for iridium-193. The mass is 193.0 amu, and the percent abundance is 0.6242. Multiply these values: 193.0 amu * 0.6242 = 120.3936 amu.
4. Add the results from steps 2 and 3 together: 71.9428 amu + 120.3936 amu = 192.3364 amu.
Therefore, the atomic mass of iridium is approximately 192.34 amu.