Use the Fundamental Theorem of Calculus to find the area of the region bounded by the x-axis and the graph of y = 4 x3 − 4 x.

Answer:

(1) Use the Fundamental Theorem of Calculus to find the average value of f(x) = e0.9 x between x = 0 and x = 2.
Answer:
(2) Draw the graph of f(x) on your calculator. Find the average value on the graph. Finally give the exact x value for which f(x) = the average value.
Answer for the x value:

To use the Fundamental Theorem of Calculus to find the area of the region bounded by the x-axis and the graph of a function, you need to follow these steps:

1. Integrate the function from the lower x-value to the upper x-value.
In this case, we need to integrate the function y = 4x^3 - 4x from x = a to x = b.

∫[a to b] (4x^3 - 4x) dx

2. Evaluate the antiderivative of the function.
The antiderivative of 4x^3 is (4/4)x^4 = x^4, and the antiderivative of -4x is (-4/2)x^2 = -2x^2.

∫[a to b] (4x^3 - 4x) dx = [x^4 - 2x^2] from a to b

3. Evaluate the definite integral by substituting the upper x-value and the lower x-value into the antiderivative and subtracting the result.

Area = [b^4 - 2b^2] - [a^4 - 2a^2]

For the given function y = 4x^3 - 4x, and the region bounded by the x-axis and the graph of the function, we need to find the area by following the above steps.

Now, for the second question:

To find the average value of a function using the Fundamental Theorem of Calculus, follow these steps:

1. Evaluate the definite integral of the function from the lower x-value to the upper x-value.
In this case, we need to integrate the function f(x) = e^(0.9x) from x = a to x = b.

∫[a to b] e^(0.9x) dx

2. Evaluate the antiderivative of the function.
The antiderivative of e^(0.9x) is (1/0.9)e^(0.9x) = (10/9)e^(0.9x).

∫[a to b] e^(0.9x) dx = [(10/9)e^(0.9x)] from a to b

3. Evaluate the definite integral by substituting the upper x-value and the lower x-value into the antiderivative and subtracting the result.

Average Value = [(10/9)e^(0.9b)] - [(10/9)e^(0.9a)] / (b - a)

For the given function f(x) = e^(0.9x), and the interval [0, 2], we need to find the average value by following the above steps.

Lastly, to find the exact x-value for which f(x) equals the average value, you need to solve the equation f(x) = avg, where f(x) is the function and avg is the average value.