A compound,KBrOx, is analyzed and found to contain 52.92% Br by mass. What is the value of x?

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asked by anne
  1. Find the RMM (R) of KBrOx by adding the relative atomic mass (RAM) of the ingredients. Keep the x in the formula.
    The RAM of Bromine is 79.9,
    R=39+79.9+16x (approximate)
    79.9/R = 52.92/100
    Solve for x and round to the nearest integer.

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    posted by MathMate

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