# Calculus

Find the interval(s) where the function is increasing where and it is decreasing.
f(x)=sin(x+(pi/2)) for 0≤x≤2pi

so my derivative is f'(x)=cos(x+(pi/2))?
and my critical number is -pi/2?

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3. 👁 181
1. cosine is positive for x +pi/2 = 0 to pi/2 and from 3 pi/2 to 2 pi

when x+pi/2 = 0 then x = -pi/2 or 3pi/2
when x + pi/2 = pi/2, x = 0
so one interval is x = 3pi/2 to 0

when x+pi/2 = 3 pi/2 then x = pi
when x+pi/2 = 2 pi then x = 3 pi/2

so second interval is frm x = pi to 3 pi/2

so finally the entire interval from x = pi to x = 2 pi (which is 0) has a positive derivative, function increasing

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posted by Damon
2. Wow, so confusing. Thanks!

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posted by sh
3. So the whole interval is increasing? The function of cosx has a section of decreasing though.

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posted by sh

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