Chemistry

describe how you would make a 2.5L of a .100M KCL solution from a 5.5M stock solution

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asked by lily
  1. 2.5 l of 0.1M solution contains 0.25 moles.

    Volume of 5.5M stock solution required
    = 0.25/5.5 * 1000 ml

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    posted by MathMate
  2. 45.454545

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