An 90 kg person steps into a car of mass 2600 kg, causing it to sink 2.35 cm on its springs. Assuming no damping, with what frequency will the car and passenger vibrate on the springs?

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  1. The spring constant is
    k = (90*9.8N/0.0235 m) = 3.75^10^4 N/m

    and the vibration frequency is

    w = [1/(2 pi)]*sqrt(k/Mtotal)

    Mtotal = 2690 kg

    w = ___ s^-1

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